(25r^2-35r+10)/(5r-2)

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Solution for (25r^2-35r+10)/(5r-2) equation: 


D( r )

5*r-2 = 0

5*r-2 = 0

5*r-2 = 0

5*r-2 = 0 // + 2

5*r = 2 // : 5

r = 2/5

r in (-oo:2/5) U (2/5:+oo)

(25*r^2-(35*r)+10)/(5*r-2) = 0

(25*r^2-35*r+10)/(5*r-2) = 0

25*r^2-35*r+10 = 0

5*(5*r^2-7*r+2) = 0

5*r^2-7*r+2 = 0

DELTA = (-7)^2-(2*4*5)

DELTA = 9

DELTA > 0

r = (9^(1/2)+7)/(2*5) or r = (7-9^(1/2))/(2*5)

r = 1 or r = 2/5

5*(r-2/5)*(r-1) = 0

(5*(r-2/5)*(r-1))/(5*r-2) = 0

( r-1 )

r-1 = 0 // + 1

r = 1

( r-2/5 )

r-2/5 = 0 // + 2/5

r = 2/5

r in { 2/5} 

r = 1

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